(x+m)2+n=x^2+4x-6

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Solution for (x+m)2+n=x^2+4x-6 equation:


Simplifying
(x + m) * 2 + n = x2 + 4x + -6

Reorder the terms:
(m + x) * 2 + n = x2 + 4x + -6

Reorder the terms for easier multiplication:
2(m + x) + n = x2 + 4x + -6
(m * 2 + x * 2) + n = x2 + 4x + -6
(2m + 2x) + n = x2 + 4x + -6

Reorder the terms:
2m + n + 2x = x2 + 4x + -6

Reorder the terms:
2m + n + 2x = -6 + 4x + x2

Solving
2m + n + 2x = -6 + 4x + x2

Solving for variable 'm'.

Move all terms containing m to the left, all other terms to the right.

Add '-1n' to each side of the equation.
2m + n + -1n + 2x = -6 + 4x + -1n + x2

Combine like terms: n + -1n = 0
2m + 0 + 2x = -6 + 4x + -1n + x2
2m + 2x = -6 + 4x + -1n + x2

Reorder the terms:
2m + 2x = -6 + -1n + 4x + x2

Add '-2x' to each side of the equation.
2m + 2x + -2x = -6 + -1n + 4x + -2x + x2

Combine like terms: 2x + -2x = 0
2m + 0 = -6 + -1n + 4x + -2x + x2
2m = -6 + -1n + 4x + -2x + x2

Combine like terms: 4x + -2x = 2x
2m = -6 + -1n + 2x + x2

Divide each side by '2'.
m = -3 + -0.5n + x + 0.5x2

Simplifying
m = -3 + -0.5n + x + 0.5x2

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